Choose the incorrect statement.

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(C) $1$. In $PH_3$ and $PF_3$,the central atom $P$ has a lone pair. Since $F$ is more electronegative than $H$,the bond pairs in $PF_3$ are closer to

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The direction of dipole moment in $CO$ molecule is from $O 	o C$ due to backbonding.

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(C) $1$. In $PH_3$ and $PF_3$,the central atom $P$ has a lone pair. Since $F$ is more electronegative than $H$,the bond pairs in $PF_3$ are closer to $F$,reducing repulsion between bond pairs,leading to a smaller bond angle in $PF_3$ compared to $PH_3$. Thus,$PH_3 > PF_3$ is correct.$2$. In $BX_3$ molecules,the bond angle is $120^{\circ}$ for all due to $sp^2$ hybridization. Thus,$BF_3 = BCl_3 = BBr_3 = BI_3$ is correct.$3$. In $CO$,the formal charge on $C$ is $-1$ and on $O$ is $+1$. The dipole moment direction is from $C$ to $O$ (from negative to positive end). The statement claiming $O 	o C$ is incorrect.$4$. The bond angle order $OF_2 (103^{\circ}) < H_2O (104.5^{\circ}) < OCl_2 (111^{\circ}) < O(SiH_3)_2 (144^{\circ})$ is correct due to increasing steric repulsion and backbonding in $O(SiH_3)_2$.

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