Choose the pair of species in which the oxida | vedclass

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(A) To find the oxidation number of nitrogen $(N)$ in each species:$1$. In $NO_2^-$: $x + 2(-2) = -1 \implies x - 4 = -1 \implies x = +3$.$2$. In $N_2

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$NO_2^-, N_2O_3$

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(A) To find the oxidation number of nitrogen $(N)$ in each species:$1$. In $NO_2^-$: $x + 2(-2) = -1 \implies x - 4 = -1 \implies x = +3$.$2$. In $N_2O_3$: $2x + 3(-2) = 0 \implies 2x - 6 = 0 \implies 2x = 6 \implies x = +3$.Since both $NO_2^-$ and $N_2O_3$ have nitrogen in the $+3$ oxidation state,the correct pair is $NO_2^-, N_2O_3$.

Choose the pair of species in which the oxidation number of nitrogen is the same.

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