Chromium metal crystallises in a body-centred | vedclass

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(C) For a $bcc$ crystal, the relationship between the atomic radius $(r)$ and the edge length $(a)$ is given by $r = \frac{\sqrt{3}}{4} a$.Given $a =

Vedclass · Accepted Answer

$124.27$

Vedclass · Answer

(C) For a $bcc$ crystal, the relationship between the atomic radius $(r)$ and the edge length $(a)$ is given by $r = \frac{\sqrt{3}}{4} a$.Given $a = 287 \, pm$.Substituting the value: $r = \frac{1.732}{4} 	imes 287$.$r = 0.433 	imes 287 = 124.27 \, pm$.Thus, the atomic radius of chromium is $124.27 \, pm$.Therefore, option $(C)$ is the correct answer.

Chromium metal crystallises in a body-centred cubic $(bcc)$ lattice. The edge length of the unit cell is found to be $287 \, pm$. The atomic radius of chromium will be ............. $pm$.

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