cis-2-butene xrightarrow{HBr/text{Peroxide}} | vedclass

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(A) The reaction of cis-$2$-butene with $HBr$ in the presence of peroxide follows a free radical addition mechanism.First,the peroxide generates a bro

Vedclass · Accepted Answer

Racemic

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(A) The reaction of cis-$2$-butene with $HBr$ in the presence of peroxide follows a free radical addition mechanism.First,the peroxide generates a bromine radical $(Br^{\bullet})$.This radical adds to the double bond of cis-$2$-butene to form a secondary alkyl radical intermediate $(CH_3-CH^{\bullet}-CH(Br)-CH_3)$.Since the radical carbon is $sp^2$ hybridized and planar,the hydrogen atom can abstract from either side of the radical center with equal probability.This leads to the formation of both $(R)$-$2$-bromobutane and $(S)$-$2$-bromobutane in equal amounts.$A$ $50:50$ mixture of enantiomers is known as a racemic mixture.

cis-$2$-butene $\xrightarrow{HBr/\text{Peroxide}}$ product; Product of the reaction is:

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