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(A) $1$. Mobility $(\mu)$ is defined as the drift velocity per unit electric field: $\mu = \frac{v_d}{E}$. Thus,$A \rightarrow R$.$2$. Electrical cond

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$A \rightarrow R ; B \rightarrow S ; C \rightarrow P ; D \rightarrow Q$

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(A) $1$. Mobility $(\mu)$ is defined as the drift velocity per unit electric field: $\mu = \frac{v_d}{E}$. Thus,$A ightarrow R$.$2$. Electrical conductivity $(\sigma)$ is the ratio of current density $(J)$ to the electric field $(E)$: $\sigma = \frac{J}{E}$. Thus,$B ightarrow S$.$3$. Relaxation time $(	au)$ is related to resistivity $(ho)$ by the formula $ho = \frac{m}{ne^2 	au}$,which implies $	au = \frac{m}{ne^2 ho}$. Thus,$C ightarrow P$.$4$. Current $(I)$ is given by the relation $I = neAv_d$,where $n$ is electron density,$e$ is charge,$A$ is area,and $v_d$ is drift velocity. Thus,$D ightarrow Q$.Therefore,the correct matching is $A ightarrow R, B ightarrow S, C ightarrow P, D ightarrow Q$.

$A$. Mobility	$P$. $\frac{m}{ne^2 \rho}$
$B$. Electrical conductivity	$Q$. $neAv_{d}$
$C$. Relaxation period	$R$. $\frac{v_{d}}{E}$
$D$. Current	$S$. $\frac{J}{E}$

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