(C) The mass of carbon in $2.64 \, g$ of $CO_2$ is: $m_C = \frac{12}{44} \times 2.64 = 0.72 \, g$.The mass of hydrogen in $1.08 \, g$ of $H_2O$ is: $m

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(C) The mass of carbon in $2.64 \, g$ of $CO_2$ is: $m_C = \frac{12}{44} \times 2.64 = 0.72 \, g$.The mass of hydrogen in $1.08 \, g$ of $H_2O$ is: $m_H = \frac{2}{18} \times 1.08 = 0.12 \, g$.The mass of oxygen in the compound is: $m_O = \text{Total mass} - (m_C + m_H) = 1.80 - (0.72 + 0.12) = 1.80 - 0.84 = 0.96 \, g$.The percentage of oxygen is: $\% \, O = \frac{0.96}{1.80} \times 100 = 53.33 \%$.

Class 11 Chemistry Some Basic Concepts of Chemistry Percentage composition and Molecular formula

Medium

Complete combustion of $1.80 \, g$ of an oxygen-containing compound $(C_xH_yO_z)$ gave $2.64 \, g$ of $CO_2$ and $1.08 \, g$ of $H_2O$. The percentage of oxygen in the organic compound is

JEE MAIN 2021 All JEE MAIN

A
$51.63$
B
$63.53$
C
$53.33$
D
$50.33$

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Some Basic Concepts of Chemistry

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Percentage composition and Molecular formula

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Complete combustion of $1.80 \, g$ of an oxygen-containing compound $(C_xH_yO_z)$ gave $2.64 \, g$ of $CO_2$ and $1.08 \, g$ of $H_2O$. The percentage of oxygen in the organic compound is

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