Complete reduction of benzene-diazonium chlor | vedclass

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Question

(B) The reduction of $benzene-diazonium$ chloride $(C_6H_5N_2Cl)$ with $Zn/HCl$ is a strong reduction process. It leads to the formation of $phenylhyd

Vedclass · Accepted Answer

Phenylhydrazine

Vedclass · Answer

(B) The reduction of $benzene-diazonium$ chloride $(C_6H_5N_2Cl)$ with $Zn/HCl$ is a strong reduction process. It leads to the formation of $phenylhydrazine$ $(C_6H_5NHNH_2)$ as the final product. Note: While mild reducing agents like $SnCl_2/HCl$ or $Na_2SO_3$ can produce $phenylhydrazine$,strong reduction with $Zn/HCl$ also yields $phenylhydrazine$ as the primary product.

Complete reduction of $benzene-diazonium$ chloride with $Zn/HCl$ gives:

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