Complete the following nuclear reaction:
${ }_{0}^{1} n+{ }_{92}^{235} U \rightarrow{ }_{92}^{236} U \rightarrow$ $\qquad$ $+{ }_{41}^{99} Nb+$ $\qquad$.

  • A
    ${ }_{56}^{144} Ba, 3{ }_{0}^{1} n$
  • B
    ${ }_{51}^{133} Sb, 4{ }_{0}^{1} n$
  • C
    ${ }_{54}^{140} Xe, 2{ }_{0}^{1} n$
  • D
    ${ }_{51}^{130} Sb, 2{ }_{0}^{1} n$

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