Compound (X) with molecular formula C_4H_8O r | vedclass

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Question

(B) $1$. The compound $(X)$ has the molecular formula $C_4H_8O$. $2$. It reacts with $2,4-DNP$, which indicates that it is an aldehyde or a ketone. $3

Vedclass · Accepted Answer

$CH_3-CH(CH_3)-CHO$

Vedclass · Answer

(B) $1$. The compound $(X)$ has the molecular formula $C_4H_8O$. $2$. It reacts with $2,4-DNP$, which indicates that it is an aldehyde or a ketone. $3$. It gives a negative haloform test, which means it does not contain a $CH_3CO-$ group or a $CH_3CH(OH)-$ group. $4$. Let us analyze the options: - Option $(A)$ is butan-$2$-one $(CH_3-CO-CH_2-CH_3)$, which is a methyl ketone and gives a positive haloform test. - Option $(B)$ is $2$-methylpropanal $(CH_3-CH(CH_3)-CHO)$, which is an aldehyde and does not contain a $CH_3CO-$ group, thus it gives a negative haloform test. - Option $(C)$ is cyclobutanol, which is an alcohol, not an aldehyde or ketone, so it will not react with $2,4-DNP$. - Option $(D)$ is butan-$2$-ol, which is an alcohol and gives a positive haloform test. $5$. Therefore, the correct compound is $2$-methylpropanal.

Compound $(X)$ with molecular formula $C_4H_8O$ reacts with $2,4-DNP$ to form a derivative and gives a negative haloform test. The compound $(X)$ is:

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