Compound A (C_9H_{10}O) shows a positive iodo | vedclass

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(A) $1$. Compound $A$ $(C_9H_{10}O)$ gives a positive iodoform test,which indicates the presence of a $CH_3CO-$ group attached to a carbon or hydrogen

Vedclass · Accepted Answer

$2-$Methylacetophenone

Vedclass · Answer

(A) $1$. Compound $A$ $(C_9H_{10}O)$ gives a positive iodoform test,which indicates the presence of a $CH_3CO-$ group attached to a carbon or hydrogen atom.$2$. Oxidation of $A$ with $KMnO_4/KOH$ yields acid $B$ $(C_8H_6O_4)$.$3$. The anhydride of $B$ is used to prepare phenolphthalein,which identifies $B$ as phthalic acid (benzene$-1,2-$dicarboxylic acid).$4$. For $A$ to oxidize to phthalic acid,it must have two alkyl groups at the ortho positions of the benzene ring,one of which is an acetyl group $(CH_3CO-)$ and the other is a methyl group $(CH_3-)$.$5$. Therefore,$A$ is $2$-methylacetophenone.

Compound $A$ $(C_9H_{10}O)$ shows a positive iodoform test. Oxidation of $A$ with $KMnO_4/KOH$ gives acid $B$ $(C_8H_6O_4)$. The anhydride of $B$ is used for the preparation of phenolphthalein. Compound $A$ is:

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