Compound $C_4H_8Cl_2$ $(A)$ on hydrolysis gives a compound $C_4H_8O$ $(B)$ which reacts with hydroxylamine and does not give any test with Tollen's reagent. What are $(A)$ and $(B)$?

  • A
    $1,1-$Dichlorobutane and butanal
  • B
    $2,2-$Dichlorobutane and butanal
  • C
    $1,1-$Dichlorobutane and butanone
  • D
    $2,2-$Dichlorobutane and butanone

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Similar Questions

Which of the following compounds would undergo $S_N1$ reaction faster and why?
$(A)$ Cyclohexylmethyl chloride
$(B)$ Benzyl chloride

For the following reactions:
$CH_{3}CH_{2}CH_{2}Br + Z^{-} \xrightarrow[substitution]{k_s} CH_{3}CH_{2}CH_{2}Z + Br^{-}$
$CH_{3}CH_{2}CH_{2}Br + Z^{-} \xrightarrow[elimination]{k_e} CH_{3}CH=CH_{2} + HZ + Br^{-}$
where
$Z^{-} = CH_{3}CH_{2}O^{-} (A)$ or $(CH_{3})_{3}CO^{-} (B)$
$k_s$ and $k_e$ are,respectively,the rate constants for the substitution and elimination,and $\mu = \frac{k_s}{k_e}$,the correct option is:

What are $X, Y$ and $Z$ in the following reactions?
$(CH_3)_3 C-O^- Na^+ + CH_3 CH_2 Br \longrightarrow X + NaBr$
$(CH_3)_3 C-Br + CH_3 CH_2 O^- Na^+ \longrightarrow Y + Z$

Tertiary alkyl halides are practically inert to substitution by the $S_N2$ mechanism due to:

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Explain: Whether a haloalkane undergoes an elimination reaction or a substitution reaction.

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