Compound I is heated with Conc. HI to give a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of an alkyl aryl ether with concentrated $HI$ involves the cleavage of the $C-O$ bond between the alkyl group and the oxygen atom. Th

Vedclass · Accepted Answer

$A = 	ext{phenol}, B = 	ext{benzene}$

Vedclass · Answer

(D) The reaction of an alkyl aryl ether with concentrated $HI$ involves the cleavage of the $C-O$ bond between the alkyl group and the oxygen atom. This is because the $C(aryl)-O$ bond has partial double bond character due to resonance and is stronger. Thus,the reaction of phenyl isopropyl ether with $HI$ yields phenol $(A)$ and isopropyl iodide. However,in the context of the given options,the reaction proceeds to form phenol $(A)$. When phenol $(A)$ is heated with $Zn$ dust,it undergoes reduction to form benzene $(B)$.

Compound $I$ is heated with Conc. $HI$ to give a hydroxy compound $A$ which is further heated with $Zn$ dust to give compound $B$. Identify $A$ and $B$.

Similar Questions

Arrange the following phenols in decreasing order of their $pK_{a}$ values:
$(A)$ Phenol
$(B)$ ortho-Nitrophenol
$(C)$ meta-Nitrophenol
$(D)$ para-Nitrophenol

An organic compound $C_6H_7N$ on reaction with $NaNO_2 / HCl$ at $273-278 \ K$ followed by warming with water gives $B$. $B$ reacts with concentrated $HNO_3$ to give $C$. What is $C$?

In which of the following,ortho/para substitution by an electrophile is very facile?

Explain why the $-OH$ group in phenols is more strongly held as compared to the $-OH$ group in alcohols?

Identify the product $P$ obtained in the following reaction: $C_6H_5OH + HCHO \xrightarrow{\text{Acid}} P$

Vedclass Test Series

Exam Paper Generator

Online Exam Module