CompoundTotal stereoisomersA. [Co(en)_2Cl_2]^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) . $[Co(en)_2Cl_2]^+$: This complex shows cis-trans isomerism. The cis-isomer is optically active ($2$ enantiomers) and the trans-isomer is optical

Vedclass · Accepted Answer

$A-Q, B-P, C-P, D-P$

Vedclass · Answer

(B) . $[Co(en)_2Cl_2]^+$: This complex shows cis-trans isomerism. The cis-isomer is optically active ($2$ enantiomers) and the trans-isomer is optically inactive. Total stereoisomers = $2 + 1 = 3$ $(Q)$.$B$. $[Co(en)_3]Cl_3$: This complex has $2$ optical isomers (enantiomers) and no geometric isomers. Total stereoisomers = $2$ $(P)$.$C$. $[Pt(NH_3)_2Cl_2]$: This is a square planar complex showing cis-trans isomerism. Both are optically inactive. Total stereoisomers = $2$ $(P)$.$D$. $[Pt(NH_3)_3Cl_3]^+$: This is an octahedral complex showing facial (fac) and meridional (mer) isomers. Both are optically inactive. Total stereoisomers = $2$ $(P)$.Therefore,the correct matching is $A-Q, B-P, C-P, D-P$.

Compound Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$ $P$. $2$
$B$. $[Co(en)_3]Cl_3$ $Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$ $R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$ $S$. $5$

Match the compounds with their total number of stereoisomers and select the correct code:

Similar Questions

The most paramagnetic complex is

In the nitroprusside ion,the iron exists as $Fe^{2+}$ and $NO$ as $NO^{+}$ rather than $Fe^{3+}$ and $NO$ respectively. These forms of ions are established with the help of

The existence of two different colored complexes of $[Co(NH_3)_4Cl_2]^+$ is due to which of the following?

Which of the following outer octahedral complexes have the same number of unpaired electrons?
$1$. $[MnCl_6]^{3-}$
$2$. $[FeF_6]^{3-}$
$3$. $[CoF_6]^{3-}$
$4$. $[Ni(NH_3)_6]^{2+}$

Which of the following complexes shows optical isomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Compound	Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$	$P$. $2$
$B$. $[Co(en)_3]Cl_3$	$Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$	$R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$	$S$. $5$

CompoundTotal stereoisomers$A$. $[Co(en)_2Cl_2]^+$$P$. $2$$B$. $[Co(en)_3]Cl_3$$Q$. $3$$C$. $[Pt(NH_3)_2Cl_2]$$R$. $4$$D$. $[Pt(NH_3)_3Cl_3]^+$$S$. $5$Match the compounds with their total number of stereoisomers and select the correct code: