Compute the difference in masses of 10^{3} , | vedclass

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Question

(A) $Mg^{2+}$ ion and a $Mg$ atom differ by two electrons.$10^{3} \, 	ext{mol}$ of $Mg^{2+}$ ions and $Mg$ atoms would differ by $10^{3} 	imes 2 \,

Vedclass · Accepted Answer

$1.096 	imes 10^{-3} \, 	ext{kg}$

Vedclass · Answer

(A) $Mg^{2+}$ ion and a $Mg$ atom differ by two electrons.$10^{3} \, 	ext{mol}$ of $Mg^{2+}$ ions and $Mg$ atoms would differ by $10^{3} 	imes 2 \, 	ext{mol}$ of electrons.Number of electrons $= 2 	imes 10^{3} 	imes 6.022 	imes 10^{23} = 12.044 	imes 10^{26} \, 	ext{electrons}$.Mass of $2 	imes 10^{3} \, 	ext{mol}$ of electrons $= 2 	imes 10^{3} 	imes 6.022 	imes 10^{23} 	imes 9.1 	imes 10^{-31} \, 	ext{kg}$.$= 12.044 	imes 10^{26} 	imes 9.1 	imes 10^{-31} \, 	ext{kg}$.$= 109.6004 	imes 10^{-5} \, 	ext{kg}$.$= 1.096 	imes 10^{-3} \, 	ext{kg}$.

Compute the difference in masses of $10^{3} \, \text{mol}$ each of magnesium atoms and magnesium ions. (Mass of an electron $= 9.1 \times 10^{-31} \, \text{kg}$)

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