Conc. H_2SO_4 cannot be used to prepare HBr f | vedclass

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Question

(B) Concentrated $H_2SO_4$ is a strong oxidizing agent. When $NaBr$ reacts with concentrated $H_2SO_4$,it first produces $HBr$ $(NaBr + H_2SO_4 	o Na

Vedclass · Accepted Answer

oxidises $HBr$ into $Br_2$

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(B) Concentrated $H_2SO_4$ is a strong oxidizing agent. When $NaBr$ reacts with concentrated $H_2SO_4$,it first produces $HBr$ $(NaBr + H_2SO_4 	o NaHSO_4 + HBr)$. However,the produced $HBr$ is then oxidized by the concentrated $H_2SO_4$ to $Br_2$ $(2HBr + H_2SO_4 	o Br_2 + SO_2 + 2H_2O)$. Therefore,it cannot be used to prepare pure $HBr$.

Conc. $H_2SO_4$ cannot be used to prepare $HBr$ from $NaBr$ because it :

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