How does the conductivity of a strong electrolyte change upon dilution?

What benefit do we get by forming a thin layer of $Pt$ particles on the electrodes of a conductivity cell?

At $25^o C$,the molar conductivity of a $0.1 \, N \, CH_3COOH$ solution is $80 \, S \, cm^2 \, mol^{-1}$ and the molar conductivity at infinite dilution is $400 \, S \, cm^2 \, mol^{-1}$. What is the degree of dissociation $(\alpha)$ of $CH_3COOH$?

The electronic conductance does not depend on . . . . . . .

Given below are two statements $:$
Statement $I :$ Mohr's salt is composed of only three types of ions$-$ferrous,ammonium and sulphate.
Statement $II :$ If the molar conductance at infinite dilution of ferrous,ammonium and sulphate ions are $x_1, x_2$ and $x_3 \ S \ cm^2 \ mol^{-1}$,respectively then the molar conductance for Mohr's salt solution at infinite dilution would be given by $x_1+x_2+2 x_3$
In the light of the given statements,choose the correct answer from the options given below $:$

The specific conductivity of a $0.01 \ M$ salt solution is $1.061 \times 10^{-4} \ S \ cm^{-1}$. The molar conductivity of this solution is: