Consider a completely full cylindrical water | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let point $1$ be the top surface of the water and point $2$ be the hole.Applying Bernoulli's equation between points $1$ and $2$:$P_1 + \frac{1}{2

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) Let point $1$ be the top surface of the water and point $2$ be the hole.Applying Bernoulli's equation between points $1$ and $2$:$P_1 + \frac{1}{2} ho v_1^2 + ho g h_1 = P_2 + \frac{1}{2} ho v_2^2 + ho g h_2$Here,$P_1 = P_0 + \frac{F}{A} = P_0 + \frac{mg}{A}$,where $m = 50 \ kg$,$g = 10 \ m/s^2$,and $A = 0.5 \ m^2$.$P_1 = P_0 + \frac{50 	imes 10}{0.5} = P_0 + 1000 \ Pa$.$P_2 = P_0$ (atmospheric pressure).Height difference $h = h_1 - h_2 = 1.6 \ m - 0.9 \ m = 0.7 \ m$.Since the tank area is large,$v_1 \approx 0$.Substituting values:$(P_0 + 1000) + 0 + ho g (0.7) = P_0 + \frac{1}{2} ho v_2^2$$1000 + 1000 	imes 10 	imes 0.7 = \frac{1}{2} 	imes 1000 	imes v_2^2$$1000 + 7000 = 500 	imes v_2^2$$8000 = 500 	imes v_2^2$$v_2^2 = 16$$v_2 = 4 \ m/s$.

Similar Questions

An aeroplane of mass $3 \times 10^4 \, kg$ and total wing area of $120 \, m^2$ is in a level flight at some height. The difference in pressure between the upper and lower surfaces of its wings in kilopascals is $(g = 10 \, m/s^2)$.

Which fundamental law forms the basis of Bernoulli's equation?

The instrument fitted in the carburetor of an automobile to provide the correct mixture of air and fuel necessary for combustion works on which of the following principles?

Explain blood flow and heart attack with the help of Bernoulli's principle.

Vedclass Test Series

Exam Paper Generator

Online Exam Module