Consider a gas with density $\rho$ and $\bar{c}$ as the root mean square velocity of its molecules contained in a volume. If the system moves as a whole with velocity $v$,then the pressure exerted by the gas is

  • A
    $\frac{1}{3}\rho\bar{c}^2$
  • B
    $\frac{1}{3}\rho(\bar{c} + v)^2$
  • C
    $\frac{1}{3}\rho(\bar{c} - v)^2$
  • D
    $\frac{1}{3}\rho(\bar{c}^{-2} - v)^2$

Explore More

Similar Questions

The temperature of a gas is $-68^\circ C$. At what temperature in $^\circ C$ will the average kinetic energy of its molecules be twice that of at $-68^\circ C$?

The energy of all molecules of a monoatomic gas having a volume $V$ and pressure $P$ is $\frac{3}{2}PV$. The total translational kinetic energy of all molecules of a diatomic gas at the same volume and pressure is:

What is the kinetic energy of $1$ mole of a monoatomic gas at $0 \, ^\circ C$? $(R = 8.31 \, J/mol \cdot K)$

Mean kinetic energy (or average energy) per gram molecule of a monoatomic gas is given by

Increase in temperature of a gas filled in a container would lead to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo