Consider the $L-C-R$ circuit given below. The circuit is driven by a $50 \,Hz, AC$ source with peak voltage $220 \,V$. If $R=400 \,\Omega, C=200 \,\mu F$ and $L=6 \,H$,the maximum current in the circuit is closest to ............ $A$.

In an $LCR$ circuit,the capacitance is changed from $C$ to $4C$. For the same resonant frequency,the inductance should be changed from $L$ to:

When a capacitor is connected in series with an $LR$ circuit,the alternating current flowing in the circuit

$A$ series $LCR$ circuit containing an $AC$ source of $100 \ V$ has an inductor and a capacitor of reactances $24 \ \Omega$ and $16 \ \Omega$ respectively. If a resistance of $6 \ \Omega$ is connected in series,then the potential difference across the series combination of inductor and capacitor only is (in $V$)

If a resistance of $100\, \Omega$,an inductance of $0.5\, H$,and a capacitance of $10 \times 10^{-6}\, F$ are connected in series to a $50\, Hz$ $AC$ supply,then the impedance is:

$A$ circuit containing an $80 \; mH$ inductor,a resistance of $15 \; \Omega$,and a $60 \; \mu F$ capacitor in series is connected to a $230 \; V, 50 \; Hz$ supply. Obtain the average power transferred to each element of the circuit,and the total power absorbed.