Consider the electronic configuration for neu | vedclass

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(C) $(i) \ 1s^22s^22p^63s^1$ is the ground state configuration of $Na$ $(Z=11)$.$(ii) \ 1s^22s^22p^64s^1$ is an excited state configuration of $Na$ $(

Vedclass · Accepted Answer

$(a) \ T, (b) \ T, (c) \ F, (d) \ T$

Vedclass · Answer

(C) $(i) \ 1s^22s^22p^63s^1$ is the ground state configuration of $Na$ $(Z=11)$.$(ii) \ 1s^22s^22p^64s^1$ is an excited state configuration of $Na$ $(Z=11)$.Statement $(a)$ is True: Energy is required to excite an electron from the $3s$ orbital to the $4s$ orbital.Statement $(b)$ is True: Both configurations have $11$ electrons,representing $Na$.Statement $(c)$ is False: Both represent the same element $(Na)$ in different energy states.Statement $(d)$ is True: The $3s$ electron is closer to the nucleus than the $4s$ electron,so it is more tightly bound and requires more energy to remove.

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