Consider the following anions:(I) CF_3SO_3^-( | vedclass

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(B) The leaving group ability is directly proportional to the stability of the resulting anion. $A$ more stable anion is a better leaving group.$(I)$

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$I > II > IV > III$

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(B) The leaving group ability is directly proportional to the stability of the resulting anion. $A$ more stable anion is a better leaving group.$(I)$ $CF_3SO_3^-$ (Triflate): The negative charge is delocalized over three oxygen atoms,and the $CF_3$ group exerts a strong electron-withdrawing $(-I)$ effect,making it the most stable anion.$(II)$ $C_6H_5SO_3^-$ (Tosylate/Benzenesulfonate): The negative charge is delocalized over three oxygen atoms,but the phenyl group is less electron-withdrawing than $CF_3$,making it less stable than $(I)$.$(IV)$ $CH_3COO^-$ (Acetate): The negative charge is delocalized over two oxygen atoms.$(III)$ $C_6H_5O^-$ (Phenoxide): The negative charge is delocalized over carbon atoms in the ring,which is less effective than delocalization over oxygen atoms.Thus,the stability order of anions is $I > II > IV > III$,which corresponds to the leaving group ability order $I > II > IV > III$.

Consider the following anions:
$(I)$ $CF_3SO_3^-$
$(II)$ $C_6H_5SO_3^-$
$(III)$ $C_6H_5O^-$
$(IV)$ $CH_3COO^-$
When attached to $sp^3$ hybridized carbon,their leaving group ability in nucleophilic substitution reaction decreases in the order:

Similar Questions

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Consider the following anions:$(I)$ $CF_3SO_3^-$$(II)$ $C_6H_5SO_3^-$$(III)$ $C_6H_5O^-$$(IV)$ $CH_3COO^-$When attached to $sp^3$ hybridized carbon,their leaving group ability in nucleophilic substitution reaction decreases in the order: