Consider the following compounds:(i) , C_6H_5 | vedclass

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(C) The reactivity of acid chlorides towards hydrolysis depends on the magnitude of the positive charge on the carbonyl carbon atom.Electron-withdrawi

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$(ii) > (iv) > (i) > (iii)$

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(C) The reactivity of acid chlorides towards hydrolysis depends on the magnitude of the positive charge on the carbonyl carbon atom.Electron-withdrawing groups $(EWG)$ increase the positive charge on the carbonyl carbon,thereby increasing reactivity.Electron-donating groups $(EDG)$ decrease the positive charge on the carbonyl carbon,thereby decreasing reactivity.The substituents at the para-position are:$(i)$ $-H$ (no effect)$(ii)$ $-NO_2$ (strong $EWG$)$(iii)$ $-CH_3$ ($EDG$ via hyperconjugation)$(iv)$ $-CHO$ $(EWG)$Comparing the strength of $EWG$,$-NO_2$ is a stronger electron-withdrawing group than $-CHO$.Thus,the order of reactivity is: $(ii) > (iv) > (i) > (iii)$.

Consider the following compounds:
$(i) \, C_6H_5COCl$
$(ii) \, p-NO_2-C_6H_4-COCl$
$(iii) \, p-CH_3-C_6H_4-COCl$
$(iv) \, p-CHO-C_6H_4-COCl$
The correct decreasing order of their reactivity towards hydrolysis is:

Similar Questions

Identify $A$ and $B$ in the following reaction:
$CH_3-CH_3 \stackrel{B}{\longleftarrow} CH_3COOH \stackrel{A}{\longrightarrow} CH_3CH_2OH$
$A \quad B$

Acid hydrolysis of which of the following compounds yields two different organic compounds?

Which is the strongest acid? ($pK_a$ value is given in the bracket)

Compound$(s)$ which will liberate carbon dioxide with sodium bicarbonate solution is/are:
$A = \text{2,4,6-triamino phenol}$
$B = \text{Benzoic acid}$
$C = \text{Picric acid (2,4,6-trinitrophenol)}$

Explain the following and provide reasons:
$(i)$ Carboxylic acid compounds are acidic in nature.
$(ii)$ Carboxylic acid compounds are more acidic than phenol compounds.

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Consider the following compounds:$(i) \, C_6H_5COCl$$(ii) \, p-NO_2-C_6H_4-COCl$$(iii) \, p-CH_3-C_6H_4-COCl$$(iv) \, p-CHO-C_6H_4-COCl$The correct decreasing order of their reactivity towards hydrolysis is: