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(C) The given electronic configuration is $[Xe] 4f^{14} 5d^1 6s^2$. The principal quantum number of the outermost shell is $n = 6$,so the element belo

Vedclass · Accepted Answer

It belongs to $6^{th}$ period and $3^{rd}$ group.

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(C) The given electronic configuration is $[Xe] 4f^{14} 5d^1 6s^2$. The principal quantum number of the outermost shell is $n = 6$,so the element belongs to the $6^{th}$ period. The last electron enters the $5d$ orbital. For $d$-block elements,the group number is calculated as $(n-1)d + ns$ electrons. Group number $= 1 + 2 = 3$. Thus,the element $P$ (Lutetium,$Lu$) belongs to the $6^{th}$ period and $3^{rd}$ group.

Consider the following electronic configuration of an element $(P)$ : $[Xe] 4f^{14} 5d^1 6s^2$. Then,the correct statement about element $P$ is:

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