Consider the following groups:I. -OAcII. -OMe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The leaving group ability is directly proportional to the stability of the resulting anion.$1$. $-OSO_2CF_3$ (triflate) is the best leaving group

Vedclass · Accepted Answer

$IV > III > I > II$

Vedclass · Answer

(B) The leaving group ability is directly proportional to the stability of the resulting anion.$1$. $-OSO_2CF_3$ (triflate) is the best leaving group because the negative charge is highly stabilized by resonance with the $SO_2$ group and the strong electron-withdrawing effect of the $-CF_3$ group.$2$. $-OSO_2Me$ (mesylate) is the next best,as the negative charge is stabilized by resonance with the $SO_2$ group,but it lacks the strong inductive effect of the $-CF_3$ group.$3$. $-OAc$ (acetate) is a moderate leaving group where the negative charge is stabilized by resonance between two oxygen atoms.$4$. $-OMe$ (methoxide) is a poor leaving group because the negative charge is localized on the oxygen atom with no resonance stabilization.Therefore,the correct order of leaving power is $IV > III > I > II$.

Consider the following groups:
$I$. $-OAc$
$II$. $-OMe$
$III$. $-OSO_2Me$
$IV$. $-OSO_2CF_3$
The order of leaving power is:

Similar Questions

Describe the color,odor,and density of haloalkanes.

Identify the correct decreasing order of reactivity of alkyl halides with ammonia.

What is the product formed when chloroform reacts with concentrated $HNO_3$?

The correct order of reactivity of the given chlorides with acetate in acetic acid is:

The decreasing order of reactivity of the following compounds towards nucleophilic substitution $(S_{N}2)$ is :

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the following groups:$I$. $-OAc$$II$. $-OMe$$III$. $-OSO_2Me$$IV$. $-OSO_2CF_3$The order of leaving power is: