Consider the following ionization enthalpies of two elements $A$ and $B$.
Element Ionization enthalpy $(kJ \ mol^{-1})$ $(1^{st}, 2^{nd}, 3^{rd})$
$A$ $899, 1757, 14847$
$B$ $737, 1450, 7731$

Which of the following statements is correct?

  • A
    Both $A$ and $B$ belong to group $2$ where $B$ comes below $A$.
  • B
    Both $A$ and $B$ belong to group $2$ where $A$ comes below $B$.
  • C
    Both $A$ and $B$ belong to group $1$ where $B$ comes below $A$.
  • D
    Both $A$ and $B$ belong to group $1$ where $A$ comes below $B$.

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Similar Questions

Ionization energy of gaseous $Na$ atoms is $495.5 \ kJ \ mol^{-1}$. The lowest possible frequency of light that ionizes a sodium atom is $(h = 6.626 \times 10^{-34} \ J \ s, N_A = 6.022 \times 10^{23} \ mol^{-1})$.

Which of the following processes will have the maximum ionization energy?

What are the various factors due to which the ionization enthalpy of the main group elements tends to decrease down a group?

Difficult
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The ionization energy of an element is defined as:

Given below are two statements $:$
Statement $(I) :$ The first ionisation enthalpy of group $14$ elements is higher than the corresponding elements of group $13.$
Statement $(II) :$ Melting points and boiling points of group $13$ elements are in general much higher than those of the corresponding elements of group $14.$ In the light of the above statements,choose the most appropriate answer from the options given below $:$

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