Consider the following isomers of [Cr(NH_3)_2 | vedclass

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(A) In an octahedral complex of the type $[MA_2B_4]$,the $cis$ isomer has the two $A$ ligands adjacent to each other (at $90^\circ$),while the $trans$

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$I$ and $IV$ are $trans$ and $II$ and $III$ are $cis$

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(A) In an octahedral complex of the type $[MA_2B_4]$,the $cis$ isomer has the two $A$ ligands adjacent to each other (at $90^\circ$),while the $trans$ isomer has the two $A$ ligands opposite to each other (at $180^\circ$).$1$. In structure $I$,the two $NH_3$ ligands are at $180^\circ$ (opposite),so it is $trans$.$2$. In structure $II$,the two $NH_3$ ligands are at $90^\circ$ (adjacent),so it is $cis$.$3$. In structure $III$,the two $NH_3$ ligands are at $90^\circ$ (adjacent),so it is $cis$.$4$. In structure $IV$,the two $NH_3$ ligands are at $180^\circ$ (opposite),so it is $trans$.Thus,$I$ and $IV$ are $trans$,and $II$ and $III$ are $cis$.

Consider the following isomers of $[Cr(NH_3)_2 Cl_4]^-$ and identify the correct classification of these isomers as $cis$ or $trans$.

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