Consider the following pairs: OrderProperty(A | vedclass

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(A) Let us analyze each pair: $(A)$ Bond angle: The bond angles are $NO_2$ $(134^{\circ})$,$O_3$ $(116.8^{\circ})$,and $H_2O$ $(104.5^{\circ})$. Thus,

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$(A), (B) \& (C)$

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(A) Let us analyze each pair: $(A)$ Bond angle: The bond angles are $NO_2$ $(134^{\circ})$,$O_3$ $(116.8^{\circ})$,and $H_2O$ $(104.5^{\circ})$. Thus,the order $NO_2 > O_3 > H_2O$ is correct. $(B)$ Dipole moment: The dipole moments are $H_2O$ $(1.85 \ D)$,$HF$ $(1.78 \ D)$,and $NH_3$ $(1.47 \ D)$. Thus,the order $H_2O > HF > NH_3$ is correct. $(C)$ Bond length: $I_2$ has a single bond with a large atomic size,$F_2$ has a single bond with a smaller atomic size,and $N_2$ has a triple bond with a very small atomic size. Bond length order is $I_2 > F_2 > N_2$. This is correct. Therefore,all three pairs $(A), (B),$ and $(C)$ are correctly matched.

Consider the following pairs:
Order Property
$(A)$ $NO_2 > O_3 > H_2O$ Bond angle
$(B)$ $H_2O > HF > NH_3$ Dipole moment
$(C)$ $I_2 > F_2 > N_2$ Bond length

Which of the above pairs are correctly matched?

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Order	Property
$(A)$ $NO_2 > O_3 > H_2O$	Bond angle
$(B)$ $H_2O > HF > NH_3$	Dipole moment
$(C)$ $I_2 > F_2 > N_2$	Bond length

Consider the following pairs: OrderProperty$(A)$ $NO_2 > O_3 > H_2O$Bond angle$(B)$ $H_2O > HF > NH_3$Dipole moment$(C)$ $I_2 > F_2 > N_2$Bond length Which of the above pairs are correctly matched?