Consider the following reaction:
$2 HSO_{4}^{-}(aq)$ $\xrightarrow[\text{(2) Hydrolysis}]{\text{(1) Electrolysis}} H_{2}S_{2}O_{8}(aq)$ $\xrightarrow{\text{Hydrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + A(aq)$
The dihedral angle in product $A$ in its solid phase at $110 \ K$ is ....$^{\circ}$

Assertion $:$ Amount of $H_2O_2$ in a sample can be determined by treating $H_2O_2$ solution with $KI$ and followed by titration of liberated $I_2$ with sodium thiosulphate.
Reason $:$ In this titration,an intense blue colour appears which disappears at the end point.

The volume (in $mL$) of $10$ volume $H_2O_2$ solution required to completely react with $200 \ mL$ of $0.4 \ M \ KMnO_4$ solution in acidic medium is

Which of the following can reduce the decomposition of $H_2O_2$ on exposure to light?

In which of the following reactions,$H_2O_2$ acts as a reducing reagent?

Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R.$
Assertion $A:$ The dihedral angle in $H_{2}O_{2}$ in the gaseous phase is $90.2^{\circ}$ and in the solid phase is $111.5^{\circ}$.
Reason $R:$ The change in dihedral angle in the solid and gaseous phases is due to the difference in the intermolecular forces.
Choose the most appropriate answer from the options given below for $A$ and $R$.