Consider the following reaction:
$CH_3CH_2OH$ $\xrightarrow{PBr_3} X$ $\xrightarrow{alc. KOH} Y$ $\xrightarrow[(ii) H_2O, \text{heat}]{(i) H_2SO_4, \text{room temperature}} Z$
The product $Z$ is
$CH_3CH_2OH$ $\xrightarrow{PBr_3} X$ $\xrightarrow{alc. KOH} Y$ $\xrightarrow[(ii) H_2O, \text{heat}]{(i) H_2SO_4, \text{room temperature}} Z$
The product $Z$ is
- A$CH_3CH_2-O-CH_2CH_3$
- B$CH_3-CH_2-OSO_3H$
- C$CH_3CH_2OH$
- D$CH_2=CH_2$
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