Consider the following reaction $A + B \rightarrow C$.
The time taken for $A$ to become $1/4$ of its initial concentration is twice the time taken to become $1/2$ of the same. Also,when the change of concentration of $B$ is plotted against time,the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis. The overall order of the reaction is . . . . .

  • A
    $5$
  • B
    $4$
  • C
    $3$
  • D
    $1$

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What is the unit of the rate constant for a $4^{th}$ order reaction?

Determine the order of reaction on the basis of following data for the reaction $A + B \to C$.
Exp.$[A]$$[B]$Rate of reaction $(mol \ L^{-1} \ s^{-1})$
$1$$0.1$$0.1$$2 \times 10^{-3}$
$2$$0.4$$0.1$$0.8 \times 10^{-2}$
$3$$0.1$$0.2$$1.6 \times 10^{-2}$
(in $.5$)

For a gaseous reaction between $X$ and $Y$,$X + 3Y \rightarrow XY_3$,the initial rate data is given below:
$[X] = 0.1 \ M, [Y] = 0.1 \ M, \text{Rate} = 0.002 \ Ms^{-1}$
$[X] = 0.2 \ M, [Y] = 0.1 \ M, \text{Rate} = 0.002 \ Ms^{-1}$
$[X] = 0.3 \ M, [Y] = 0.2 \ M, \text{Rate} = 0.008 \ Ms^{-1}$
$[X] = 0.4 \ M, [Y] = 0.3 \ M, \text{Rate} = 0.018 \ Ms^{-1}$
What is the rate law?

The rate law for the reaction $A + B \rightarrow \text{product}$ is $\text{rate} = k[A][B]$. When will the rate of reaction increase by a factor of $2$?

If the concentration of the reactants is increased,the rate of reaction

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