Consider the following reaction sequence: CH_ | vedclass

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(D) Step $1$: Electrophilic addition of $HBr$ to $3,3$-dimethyl-$1$-butene involves a carbocation intermediate. The initially formed secondary carboca

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$CH_3-C(CH_3)=C(CH_3)-CH_3$

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(D) Step $1$: Electrophilic addition of $HBr$ to $3,3$-dimethyl-$1$-butene involves a carbocation intermediate. The initially formed secondary carbocation $CH_3-C(CH_3)_2-C^{+}H-CH_3$ undergoes a $1,2$-methyl shift to form a more stable tertiary carbocation $CH_3-C^{+}(CH_3)-CH(CH_3)_2$. $Br^{-}$ then attacks this carbocation to form $2$-bromo-$2,3$-dimethylbutane. Step $2$: Dehydrohalogenation with alcoholic $KOH$ (elimination) follows Zaitsev's rule,where the more substituted alkene is the major product. Thus,$2,3$-dimethyl-$2$-butene $(CH_3-C(CH_3)=C(CH_3)-CH_3)$ is formed as the major end product.

Consider the following reaction sequence:
$CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[2. KOH, EtOH, \text{heat}]{1. HBr}$
The major end product formed is:

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Consider the following reaction sequence: $CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[2. KOH, EtOH, \text{heat}]{1. HBr}$ The major end product formed is: