Consider the following reactions:(i) PCl_3 + | vedclass

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(D) Let us analyze the hybridization of the central atom in each reaction:$(i)$ $PCl_3$ $(sp^3)$ $	o$ $H_3PO_3$ $(sp^3)$. The hybridization remains u

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During the $(iv)$ reaction the hybridisation of $18^{th}$ group element does not change

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(D) Let us analyze the hybridization of the central atom in each reaction:$(i)$ $PCl_3$ $(sp^3)$ $	o$ $H_3PO_3$ $(sp^3)$. The hybridization remains unchanged.$(ii)$ $SF_4$ $(sp^3d)$ $	o$ $H_2SO_3$ $(sp^3)$. The hybridization changes from $sp^3d$ to $sp^3$.$(iii)$ $BCl_3$ $(sp^2)$ $	o$ $H_3BO_3$ $(sp^2)$. The hybridization remains unchanged.$(iv)$ $XeF_6$ $(sp^3d^3)$ $	o$ $XeO_3$ $(sp^3)$. The hybridization changes from $sp^3d^3$ to $sp^3$.Therefore,the statement in option $(D)$ is incorrect because the hybridization of $Xe$ changes from $sp^3d^3$ to $sp^3$.

Consider the following reactions:
$(i)$ $PCl_3 + 3H_2O \to H_3PO_3 + 3HCl$
$(ii)$ $SF_4 + 3H_2O \to H_2SO_3 + 4HF$
$(iii)$ $BCl_3 + 3H_2O \to H_3BO_3 + 3HCl$
$(iv)$ $XeF_6 + 3H_2O \to XeO_3 + 6HF$
Then according to given information the incorrect statement is

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Consider the following reactions:$(i)$ $PCl_3 + 3H_2O \to H_3PO_3 + 3HCl$$(ii)$ $SF_4 + 3H_2O \to H_2SO_3 + 4HF$$(iii)$ $BCl_3 + 3H_2O \to H_3BO_3 + 3HCl$$(iv)$ $XeF_6 + 3H_2O \to XeO_3 + 6HF$Then according to given information the incorrect statement is