Consider the following reactions:
$[P] \xrightarrow[(i) \ NaNO_2/HCl, \ 0 - 5^oC]{(ii) \ \beta-naphthol/NaOH} \text{Colored Solid}$
$[P] \xrightarrow{Br_2/H_2O} C_7H_6NBr_3$
The compound $[P]$ is:

Which of the following compounds is expected to be the most basic?

Decarboxylation of all six possible isomers of diaminobenzoic acids $C_6H_3(NH_2)_2COOH$ yields three products $A, B$ and $C$. Three acids give product $A$,two acids give product $B$ and one acid gives product $C$. The melting point of product $C$ is .....$^{\circ} C$.

In the given reaction sequence,what is $Z$?
Aniline $\xrightarrow{CH_3COCl} X$ $\xrightarrow{Br_2/AlBr_3} Y$ $\xrightarrow{H_3O^+} Z$

$Benzamide$ $\xrightarrow{Br_2 / NaOH} X$ $\xrightarrow[\text{alc. } KOH]{CHCl_3} Y$
The conversion of $X$ to $Y$ is

In the following reactions,$P$,$Q$,$R$,and $S$ are the major products.
(image)
The correct statement about $P$,$Q$,$R$,and $S$ is