Consider the following sequence of reactions: | vedclass

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(D) Let the ketone $A$ be $R-CO-R'$.$1$. Reaction with $C_2H_5MgBr$ followed by hydrolysis gives a tertiary alcohol $B$ $(R-C(OH)(C_2H_5)-R')$.$2$. De

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Propanone

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(D) Let the ketone $A$ be $R-CO-R'$.$1$. Reaction with $C_2H_5MgBr$ followed by hydrolysis gives a tertiary alcohol $B$ $(R-C(OH)(C_2H_5)-R')$.$2$. Dehydration of $B$ with $H_2SO_4$ and heat gives an alkene $C$.$3$. Ozonolysis of $C$ gives propanone $(CH_3COCH_3)$ and acetaldehyde $(CH_3CHO)$.$4$. The products of ozonolysis indicate that the alkene $C$ is $CH_3-C(CH_3)=CH-CH_3$ ($2$-methylbut$-2-$ene).$5$. Working backwards,the alcohol $B$ must be $CH_3-C(OH)(CH_3)-CH_2-CH_3$ ($2$-methylbutan$-2-$ol).$6$. This alcohol is formed by the reaction of butan$-2-$one $(CH_3COCH_2CH_3)$ with $CH_3MgBr$ $OR$ by the reaction of propanone $(CH_3COCH_3)$ with $C_2H_5MgBr$.$7$. Given the sequence uses $C_2H_5MgBr$,the ketone $A$ must be propanone $(CH_3COCH_3)$.

Consider the following sequence of reactions:
Ketone $A$ $\xrightarrow[2. H_2O]{1. C_2H_5MgBr} B$ $\xrightarrow[- H_2O]{H_2SO_4, \text{Heat}} C$ $\xrightarrow[2. Zn, H_2O]{1. O_3} \text{Propanone} + \text{Acetaldehyde}$
The ketone $A$ is:

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Consider the following sequence of reactions:Ketone $A$ $\xrightarrow[2. H_2O]{1. C_2H_5MgBr} B$ $\xrightarrow[- H_2O]{H_2SO_4, \text{Heat}} C$ $\xrightarrow[2. Zn, H_2O]{1. O_3} \text{Propanone} + \text{Acetaldehyde}$The ketone $A$ is: