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(C) $1$. The starting material is $2-	ext{benzylbenzoic acid}$.$2$. Treatment with $SOCl_2$ converts the carboxylic acid group into an acid chloride

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$9,10-$Dihydroanthracene

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(C) $1$. The starting material is $2-	ext{benzylbenzoic acid}$.$2$. Treatment with $SOCl_2$ converts the carboxylic acid group into an acid chloride $(-COCl)$.$3$. Subsequent treatment with anhydrous $AlCl_3$ induces an intramolecular Friedel-Crafts acylation,forming the cyclic ketone,anthraquinone (compound $A$).$4$. The final step uses Clemmensen reduction $(Zn-Hg, 	ext{Conc. } HCl)$,which reduces the carbonyl group $(C=O)$ to a methylene group $(-CH_2-)$.$5$. The reduction of anthraquinone yields $9,10-	ext{dihydroanthracene}$ (compound $B$).

Consider the following sequence of reactions:
$2-\text{benzylbenzoic acid}$ $\xrightarrow[2. \text{anhyd. } AlCl_3]{1. SOCl_2} A$ $\xrightarrow{Zn-Hg, \text{Conc. } HCl} B$
The end product $(B)$ is:

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Total number of nucleophiles from the following is $:-$ $NH_3, PhSH, (H_3C)_2S, H_2C=CH_2, \stackrel{\ominus}{O}H, H_3O^{\oplus}, (CH_3)_2CO, CH_3CH=NCH_3$

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Predict the product $B$ in the sequence of reaction:
$HC \equiv CH$ $\xrightarrow{30\% \ H_2SO_4, HgSO_4} A$ $\xrightarrow{dil. \ NaOH} B$

Which of the following reagents reacts differently with $HCHO$,$CH_3CHO$,and $CH_3COCH_3$?

$PhMgBr$ [Excess] + $CH_3COCl \xrightarrow{H_3O^+}$
The final product of the above reaction is:

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Consider the following sequence of reactions:$2-\text{benzylbenzoic acid}$ $\xrightarrow[2. \text{anhyd. } AlCl_3]{1. SOCl_2} A$ $\xrightarrow{Zn-Hg, \text{Conc. } HCl} B$The end product $(B)$ is: