Consider the following statements about the h | vedclass

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(C) Statement $(I)$ is incorrect because the reaction between $NaH$ and $H_2O$ releases hydrogen gas,not oxygen gas: $NaH + H_2O \rightarrow NaOH + H_

Vedclass · Accepted Answer

$II$ & $IV$ only

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(C) Statement $(I)$ is incorrect because the reaction between $NaH$ and $H_2O$ releases hydrogen gas,not oxygen gas: $NaH + H_2O \rightarrow NaOH + H_2 \uparrow$. Statement $(II)$ is correct; $CH_4$ and $SiH_4$ have the required number of electrons to form normal covalent bonds,making them electron-precise hydrides. Statement $(III)$ is incorrect; $NH_3$ and $H_2O$ are electron-rich hydrides because they possess lone pairs of electrons on the central atom. Statement $(IV)$ is correct; hydrides of $Be$ and $Mg$ ($BeH_2$ and $MgH_2$) are electron-deficient and exist in polymeric structures. Thus,statements $(II)$ and $(IV)$ are correct.

List $I$	List $II$
$A.$ Cobalt catalyst	$I.$ $(H_2 + Cl_2)$ production
$B.$ Syngas	$II.$ Water gas production
$C.$ Nickel catalyst	$III.$ Coal gasification
$D.$ Brine solution	$IV.$ Methanol production

Similar Questions

The hydride that is $NOT$ electron deficient is

In the Bosch process,which of the following gases is used for the production of $H_2$ gas?

Match List $I$ with List $II$
List $I$ List $II$
$A.$ Cobalt catalyst $I.$ $(H_2 + Cl_2)$ production
$B.$ Syngas $II.$ Water gas production
$C.$ Nickel catalyst $III.$ Coal gasification
$D.$ Brine solution $IV.$ Methanol production

Choose the correct answer from the options given below:

Dihydrogen can be prepared by which of the following reactions?
$(I)$ Reaction of granulated $Zn$ with dil. $HCl$
$(II)$ Reaction of $Zn$ with aq. $NaOH$
$(III)$ By heating calcium hydrogen carbonate

What are metallic or interstitial hydrides? How do they differ from molecular hydrides?

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