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(D) Einstein's photoelectric equation is given by $K_{max} = h
u - \phi_0$,where $K_{max} = eV_s$ ($V_s$ is the stopping potential).$(I)$ The instant

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Statements $I, II$ and $III$ are correct

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(D) Einstein's photoelectric equation is given by $K_{max} = h
u - \phi_0$,where $K_{max} = eV_s$ ($V_s$ is the stopping potential).$(I)$ The instantaneous nature of emission suggests that energy is transferred in discrete packets (photons),supporting the quantum theory.$(II)$ The existence of a threshold frequency $(
u_0)$ implies that a photon must have a minimum energy $h
u_0$ to eject an electron,which directly supports the photon model.$(III)$ Since $eV_s = h
u - \phi_0$,the stopping potential $V_s$ is a linear function of frequency $
u$. This confirms the relationship $E = h
u$.$(IV)$ While the photocurrent is proportional to intensity,this is a property of the number of photons and does not specifically prove the energy-frequency relationship of a single photon.Therefore,statements $(I), (II),$ and $(III)$ are the ones that indicate light consists of quanta with energy proportional to frequency.

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