Consider the following table: Gas a / | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The constant $a$ represents the magnitude of intermolecular forces of attraction. $A$ higher value of $a$ implies stronger attraction,which pulls

Vedclass · Accepted Answer

Gas $C$ will occupy more volume than gas $A$; gas $B$ will be more compressible than gas $D$.

Vedclass · Answer

(D) The constant $a$ represents the magnitude of intermolecular forces of attraction. $A$ higher value of $a$ implies stronger attraction,which pulls molecules closer,resulting in a smaller volume occupied.For gases $A$ and $C$,$b$ is the same $(0.05196)$. Since $a_A (642.32) > a_C (431.91)$,gas $A$ has stronger intermolecular forces and occupies less volume than gas $C$. Thus,gas $C$ occupies more volume than gas $A$.For gases $B$ and $D$,$a$ is the same $(155.21)$. The constant $b$ represents the excluded volume per mole. $A$ smaller value of $b$ means the molecules occupy less space,making the gas more compressible.Since $b_B (0.04136) < b_D (0.4382)$,gas $B$ is more compressible than gas $D$.

Gas	$a / (kPa \cdot dm^6 \cdot mol^{-2})$	$b / (dm^3 \cdot mol^{-1})$
$A$	$642.32$	$0.05196$
$B$	$155.21$	$0.04136$
$C$	$431.91$	$0.05196$
$D$	$155.21$	$0.4382$

Consider the following table:

Gas $a / (kPa \cdot dm^6 \cdot mol^{-2})$ $b / (dm^3 \cdot mol^{-1})$

$A$ $642.32$ $0.05196$

$B$ $155.21$ $0.04136$

$C$ $431.91$ $0.05196$

$D$ $155.21$ $0.4382$

$a$ and $b$ are van der Waals constants. The correct statement about the gases is:

Similar Questions

The Vander Waals equation for $0.5 \ mol$ of a gas is:

The $Van \text{ der } Waals$ equation explains the behaviour of

The compressibility factor of a real gas at high pressure is

For $1$ mol of a real gas kept at constant temperature $T$,the graph of $PV$ vs $P$ intersects the $PV$ axis at $20$. Hence,the temperature $T$ is ($R$ = universal gas constant).

When helium is allowed to expand into vacuum,a heating effect is observed. The reason for this is that

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the following table: Gas $a / (kPa \cdot dm^6 \cdot mol^{-2})$ $b / (dm^3 \cdot mol^{-1})$ $A$ $642.32$ $0.05196$ $B$ $155.21$ $0.04136$ $C$ $431.91$ $0.05196$ $D$ $155.21$ $0.4382$ $a$ and $b$ are van der Waals constants. The correct statement about the gases is: