Consider the given reaction,the product 'X' i | vedclass

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(D) $1$. The reaction of $5,5$-dimethylcyclopentanone with $CH_3CHO$ in the presence of $NaOH$ is an aldol condensation reaction,which produces a $\be

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(D) $1$. The reaction of $5,5$-dimethylcyclopentanone with $CH_3CHO$ in the presence of $NaOH$ is an aldol condensation reaction,which produces a $\beta$-hydroxy ketone intermediate.$2$. This intermediate contains a $CH_3CH(OH)-$ group,which is susceptible to the iodoform reaction.$3$. Treatment with $I_2/NaOH$ performs the iodoform reaction,converting the $CH_3CH(OH)-$ group into a carboxylate group $(-COO^-Na^+)$ and producing $CHI_3$ (yellow precipitate).$4$. The filtrate containing the carboxylate is then acidified with $HCl$ to yield the final product $'X'$,which is $5,5$-dimethyl$-2-$oxocyclopentanecarboxylic acid.

Consider the given reaction,the product $'X'$ is:

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