(B) The electronic configuration of $Cr$ $(Z = 24)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5, 4s^1$.For $l = 1$ (which corresponds to $p$-orbitals),the

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(B) The electronic configuration of $Cr$ $(Z = 24)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5, 4s^1$.For $l = 1$ (which corresponds to $p$-orbitals),the electrons are in $2p^6$ and $3p^6$. Total electrons $= 6 + 6 = 12$.For $l = 2$ (which corresponds to $d$-orbitals),the electrons are in $3d^5$. Total electrons $= 5$.Therefore,the numbers of electrons with $l = 1$ and $l = 2$ are $12$ and $5$ respectively.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

Medium

Consider the ground state of $Cr$ $(Z = 24)$. The numbers of electrons with the azimuthal quantum numbers,$l = 1$ and $l = 2$ are,respectively:

AIEEE 2004 All AIEEE

A
$16$ and $4$
B
$12$ and $5$
C
$12$ and $4$
D
$16$ and $5$

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Class 11

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Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

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$A$ filled or half-filled set of $p$ or $d$-orbitals is spherically symmetric. Point out the species which has spherical symmetry.

Medium

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If the given four electronic configurations:
$(i)$ $n=4, l=1$
$(ii)$ $n=4, l=0$
$(iii)$ $n=3, l=2$
$(iv)$ $n=3, l=1$
are arranged in order of increasing energy, then the order will be:

EasyWBJEE 2017

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The allowed set of quantum numbers for an electron in a hydrogen atom is

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The number of orbitals in the fourth principal quantum number $(n = 4)$ is:

Medium

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What is the maximum number of electrons that can have the quantum numbers $n = 5$ and $m_l = +2$?

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Consider the ground state of $Cr$ $(Z = 24)$. The numbers of electrons with the azimuthal quantum numbers,$l = 1$ and $l = 2$ are,respectively:

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$A$ filled or half-filled set of $p$ or $d$-orbitals is spherically symmetric. Point out the species which has spherical symmetry.

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If the given four electronic configurations:
$(i)$ $n=4, l=1$
$(ii)$ $n=4, l=0$
$(iii)$ $n=3, l=2$
$(iv)$ $n=3, l=1$
are arranged in order of increasing energy, then the order will be: