Consider the reaction: $N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$. The equality relationship between $\frac{d[NH_3]}{dt}$ and $\frac{d[H_2]}{dt}$ is
- A$\frac{d[NH_3]}{dt} = - \frac{d[H_2]}{dt}$
- B$\frac{d[NH_3]}{dt} = - \frac{1}{3} \frac{d[H_2]}{dt}$
- C$+ \frac{d[NH_3]}{dt} = - \frac{2}{3} \frac{d[H_2]}{dt}$
- D$+ \frac{d[NH_3]}{dt} = - \frac{3}{2} \frac{d[H_2]}{dt}$
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Similar Questions
$A$ reaction,$3 X_{(g)} \rightarrow 2 Y_{(g)} + Z_{(g)}$ takes place in a closed vessel. What is the rate of formation of $Y$ (in $mol \ L^{-1} \ s^{-1}$) if the rate of disappearance of $X$ is $7.2 \times 10^{-3} \ mol \ L^{-1} \ s^{-1}$?
For the reaction $2N_2O_5(g) \rightleftharpoons 4NO_2(g) + O_2(g)$ in a closed vessel,the concentration of $NO_2$ increases by $2.0 \times 10^{-2} \ mol \ L^{-1}$ in $5 \ s$. Calculate the rate of change of concentration of $N_2O_5$.
Medium
View SolutionFor a given reaction $3A + B \to C + D$,the rate of reaction can be represented by:
Easy
View SolutionFor an elementary reaction $2A + B \longrightarrow 3C$,the rate of appearance of $C$ is $1.3 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$. The rate of disappearance of $A$ is:
The rate of disappearance of $MnO_4^-$ in the following reaction is $4.56 \times 10^{-3} \ M/s$.
$2MnO_4^- + 10I^{-} + 16H^{+} \to 2Mn^{2+} + 5I_2 + 8H_2O$
The rate of appearance of $I_2$ is:
$2MnO_4^- + 10I^{-} + 16H^{+} \to 2Mn^{2+} + 5I_2 + 8H_2O$
The rate of appearance of $I_2$ is:
Medium
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