Consider the reactions:(i) (CH_3)_2CHCH_2Br | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In reaction $(i)$,the solvent is $C_2H_5OH$,which is a weak nucleophile and a polar protic solvent. This promotes the formation of a carbocation i

Vedclass · Accepted Answer

$S_N1$ and $S_N2$

Vedclass · Answer

(B) In reaction $(i)$,the solvent is $C_2H_5OH$,which is a weak nucleophile and a polar protic solvent. This promotes the formation of a carbocation intermediate,characteristic of an $S_N1$ mechanism.In reaction $(ii)$,the reagent is $C_2H_5O^-$,which is a strong nucleophile. Strong nucleophiles favor the $S_N2$ mechanism,where the nucleophile attacks the substrate directly in a single step.Therefore,the mechanisms are $S_N1$ and $S_N2$ respectively.

Consider the reactions:
$(i) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5OH} (CH_3)_2CHCH_2OC_2H_5 + HBr$
$(ii) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5O^-} (CH_3)_2CHCH_2OC_2H_5 + Br^-$
The mechanisms of reaction $(i)$ and $(ii)$ are respectively:

Similar Questions

$C_6H_5CH_2Cl + KCN(aq.) \to X + Y$
Compounds $X$ and $Y$ are

The product $(C)$ in the following reaction sequence is:
$4-\text{Bromoethylbenzene}$ $\xrightarrow[\Delta]{Br_2} B$ $\xrightarrow{\text{aq. } KOH} C$

In solvolysis of $1,2$-dimethylpropyl $p$-toluenesulfonate in acetic acid at $75\,^oC$,how many (alkene + substitution) products will be formed?

The dipole moments of halo compounds are in the order:

What is the major product obtained when $tert-$butyl bromide is heated with silver fluoride?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the reactions:$(i) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5OH} (CH_3)_2CHCH_2OC_2H_5 + HBr$$(ii) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5O^-} (CH_3)_2CHCH_2OC_2H_5 + Br^-$The mechanisms of reaction $(i)$ and $(ii)$ are respectively: