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(B) $X$ is $C_2H_6O$. Since it reacts with $Cu$ at $573 \ K$ to give $A$,and $A$ gives a silver mirror test,$X$ must be a primary alcohol and $A$ must

Vedclass · Accepted Answer

$A: 	ext{Ethanal}, X: 	ext{Ethanol}, Y: 	ext{But-2-enal}, Z: 	ext{Semicarbazone}$

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(B) $X$ is $C_2H_6O$. Since it reacts with $Cu$ at $573 \ K$ to give $A$,and $A$ gives a silver mirror test,$X$ must be a primary alcohol and $A$ must be an aldehyde.$X = CH_3CH_2OH$ (Ethanol).$A = CH_3CHO$ (Ethanal).$2CH_3CHO \xrightarrow{^-OH, \Delta} CH_3CH=CHCHO$ ($Y$,But$-2-$enal) via Aldol condensation.$CH_3CHO + NH_2NHCONH_2 ightarrow CH_3CH=NNHCONH_2$ ($Z$,Semicarbazone).Thus,$A = 	ext{Ethanal}, X = 	ext{Ethanol}, Y = 	ext{But-2-enal}, Z = 	ext{Semicarbazone}$.

Consider the reactions and identify $A, X, Y$ and $Z$:
$X (C_2H_6O)$ $\xrightarrow{Cu, 573 \ K} A$ $\xrightarrow{[Ag(NH_3)_2]^+, ^-OH, \Delta} \text{Silver mirror}$
$A \xrightarrow{^-OH, \Delta} Y$
$A \xrightarrow{NH_2NHCONH_2} Z$

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Consider the reactions and identify $A, X, Y$ and $Z$:$X (C_2H_6O)$ $\xrightarrow{Cu, 573 \ K} A$ $\xrightarrow{[Ag(NH_3)_2]^+, ^-OH, \Delta} \text{Silver mirror}$$A \xrightarrow{^-OH, \Delta} Y$$A \xrightarrow{NH_2NHCONH_2} Z$