Consider three point charges -2Q, Q and -Q an | vedclass

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(D) According to Gauss's Law, the net electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{enclosed}}{\epsilon_0}$.$(a)$ Surface

Vedclass · Accepted Answer

$a-ii, b-iii, c-i$

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(D) According to Gauss's Law, the net electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{enclosed}}{\epsilon_0}$.$(a)$ Surface $S_1$ encloses charge $-2Q$ and $Q$. Net charge $q_{enclosed} = -2Q + Q = -Q$. Thus, flux $\phi_1 = \frac{-Q}{\epsilon_0}$. This matches (ii).$(b)$ Surface $S_2$ encloses charge $Q$ and $-Q$. Net charge $q_{enclosed} = Q + (-Q) = 0$. Thus, flux $\phi_2 = 0$. This matches (iii).$(c)$ Surface $S_3$ encloses all three charges $-2Q$, $Q$ and $-Q$. Net charge $q_{enclosed} = -2Q + Q - Q = -2Q$. Thus, flux $\phi_3 = \frac{-2Q}{\epsilon_0}$. This matches $(i)$.Therefore, the correct matching is $a-ii, b-iii, c-i$.

List-$I$	List-$II$
$(a)$ Net flux through $S_1$	$(i)$ $\frac{-2Q}{\epsilon_0}$
$(b)$ Net flux through $S_2$	(ii) $\frac{-Q}{\epsilon_0}$
$(c)$ Net flux through $S_3$	(iii) Zero

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