Class 11PhysicsNewton's Laws of Motion and FrictionMotion of Body (or Connected Bodies in horizontal or vertical) (by String or Contact)
EasyConsider two masses $m_1$ and $m_2$ connected through a pulley as shown in the figure. Mass $m_2$ starts from rest at height $h$ and falls down. With what speed does it hit the ground? (Assume no friction and massless strings and pulleys.)
- A$\sqrt{\left(\frac{m_2}{m_1+m_2}\right) g h}$
- B$\sqrt{2 g h}$
- C$\sqrt{\left(\frac{m_2}{m_1+m_2}\right) 2 g h}$
- D$\sqrt{\left(\frac{m_1}{m_1+m_2}\right) 2 g h}$
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$A$ mass of $2 \, kg$ is suspended with a thread $AB$ as shown in the figure. $A$ thread $CD$ of the same type is attached to the other end of the $2 \, kg$ mass. The lower thread is pulled gradually,harder and harder in the downward direction,so as to apply force on $AB$. Which of the threads will break and why?
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View SolutionThree blocks are connected as shown in the figure on a horizontal frictionless table. If $m_1 = 1 \, kg, m_2 = 8 \, kg, m_3 = 27 \, kg$ and $T_3 = 36 \, N$,then $T_2$ will be ............ $N$.
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View SolutionTwo masses $m_1$ and $m_2$ are placed on a smooth horizontal surface and are connected by a string of negligible mass. $A$ horizontal force $F$ is applied on the mass $m_2$ as shown in the figure. The tension in the string is
For the given arrangement of blocks on a frictionless surface,the tension $T_2$ is:
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View Solution$A$ force $F = 10t$ acts on a block of mass $10 \, kg$ as shown in the figure. Find the time $t$ when the block loses contact with the surface.
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