Consider two reactions:I. Zn + conc. HNO_3 (h | vedclass

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(B) The reaction of zinc with nitric acid depends on the concentration of the acid.For reaction $I$: Zinc reacts with concentrated $HNO_3$ to produce

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$NO_2, N_2O$

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(B) The reaction of zinc with nitric acid depends on the concentration of the acid.For reaction $I$: Zinc reacts with concentrated $HNO_3$ to produce nitrogen dioxide $(NO_2)$.$Zn + 4HNO_3 (	ext{conc.}) 	o Zn(NO_3)_2 + 2NO_2 + 2H_2O$Thus,$X = NO_2$.For reaction $II$: Zinc reacts with dilute $HNO_3$ to produce nitrous oxide $(N_2O)$.$4Zn + 10HNO_3 (	ext{dil.}) 	o 4Zn(NO_3)_2 + N_2O + 5H_2O$Thus,$Y = N_2O$.Therefore,the compounds $X$ and $Y$ are $NO_2$ and $N_2O$ respectively.

Consider two reactions:
$I$. $Zn +$ conc. $HNO_3$ (hot) $\to Zn(NO_3)_2 + X + H_2O$
$II$. $Zn +$ dil. $HNO_3$ (cold) $\to Zn(NO_3)_2 + Y + H_2O$
Compounds $X$ and $Y$ are respectively:

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Consider two reactions:$I$. $Zn +$ conc. $HNO_3$ (hot) $\to Zn(NO_3)_2 + X + H_2O$$II$. $Zn +$ dil. $HNO_3$ (cold) $\to Zn(NO_3)_2 + Y + H_2O$Compounds $X$ and $Y$ are respectively: