(C) For the $1^{st}$ jar:Number of moles of $H_2 = \frac{2 \ g}{2 \ g/mol} = 1 \ mol$.Number of molecules of $H_2 = 1 \times N_A = 6.022 \times 10^{23

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(C) For the $1^{st}$ jar:Number of moles of $H_2 = \frac{2 \ g}{2 \ g/mol} = 1 \ mol$.Number of molecules of $H_2 = 1 \times N_A = 6.022 \times 10^{23}$ molecules.For the $2^{nd}$ jar:Number of moles of $N_2 = \frac{28 \ g}{28 \ g/mol} = 1 \ mol$.Number of molecules of $N_2 = 1 \times N_A = 6.022 \times 10^{23}$ molecules.Since both jars contain $1 \ mol$ of gas,they contain the same number of molecules.

Class 11 Chemistry Some Basic Concepts of Chemistry The mole concept

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Consider two sealed jars of equal volume. One contains $2 \ g$ of hydrogen at $200 \ K$ and the other contains $28 \ g$ of nitrogen at $400 \ K$. The gases in the two jars will have

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the same pressure
B
the same average kinetic energy
C
the same number of molecules
D
the same average molecular speed

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Some Basic Concepts of Chemistry

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The mole concept

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Consider two sealed jars of equal volume. One contains $2 \ g$ of hydrogen at $200 \ K$ and the other contains $28 \ g$ of nitrogen at $400 \ K$. The gases in the two jars will have

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