Considering H_2O as a weak field ligand,the n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The atomic number of $Mn$ is $25$. The electronic configuration of $Mn$ is $[Ar] 3d^5 4s^2$.In the complex $[Mn(H_2O)_6]^{2+}$,the oxidation state

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) The atomic number of $Mn$ is $25$. The electronic configuration of $Mn$ is $[Ar] 3d^5 4s^2$.In the complex $[Mn(H_2O)_6]^{2+}$,the oxidation state of $Mn$ is $+2$. Thus,the configuration of $Mn^{2+}$ is $[Ar] 3d^5$.Since $H_2O$ is a weak field ligand,it does not cause pairing of electrons in the $d$-orbitals.Therefore,the $5$ electrons in the $3d$ subshell remain unpaired.Hence,the number of unpaired electrons is $5$.

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

Similar Questions

In the complex $cis-[Cr(en)_2Cl_2]^+$,the oxidation state of $Cr$,the type of $d$-orbital involved in the valence shell,and the coordination number are respectively:

Identify the number of unpaired electrons present and the geometry of the $[Co(NH_3)_6]^{3+}$ complex, respectively.

How many unpaired electrons are present in $Ni^{2+}$?

The hybridization of the complex $[CrCl_2(NO_2)_2(NH_3)_2]^-$ is

The complex ion which has no $d$ electrons in the central metal atom is

Vedclass Test Series

Exam Paper Generator

Online Exam Module