Considering entropy $(S)$ as a thermodynamic parameter,the criterion for the spontaneity of any process is
- A$\Delta S_{system} > 0$ only
- B$\Delta S_{surroundings} > 0$ only
- C$\Delta S_{system} + \Delta S_{surroundings} > 0$
- D$\Delta S_{system} - \Delta S_{surroundings} > 0$
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Similar Questions
Calculate the entropy change of the surrounding if $2 \ moles$ of $H_2$ and $1 \ mole$ of $O_2$ gas combine to form $2 \ moles$ of liquid water by releasing $525 \ kJ$ of heat to the surrounding at constant pressure and at $300 \ K$. (in $J \ K^{-1}$)
At $298 \, K$ and $1 \, atm$ pressure,the entropies of $H_2(g)$,$Cl_2(g)$,and $HCl(g)$ are $130.6$,$223$,and $186.7 \, J \, K^{-1} \, mol^{-1}$ respectively. What is the entropy change for the reaction $H_2(g) + Cl_2(g) \rightarrow 2HCl(g)$ in $J \, K^{-1} \, mol^{-1}$?
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View SolutionIf the enthalpy of vaporization for water is $186.5 \ kJ \ mol^{-1}$,the entropy of its vaporization will be ...... $J \ K^{-1} \ mol^{-1}$ (Assume the boiling point of water is $373 \ K$).
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View SolutionCalculate the entropy change for melting $1 \ g$ of ice at $0^{\circ} C$ in $J \ g^{-1} K^{-1}$,if the heat of fusion of ice at $0^{\circ} C$ is $80 \ J \ g^{-1}$.
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View SolutionThe molar heat of vaporisation of a liquid is $6 \ kJ \ mol^{-1}$. If the entropy change is $16 \ J \ mol^{-1} \ K^{-1}$,the boiling point of the liquid is:
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