Construct a right triangle whose base is $6\,cm$ and the sum of its hypotenuse and other side is $9\,cm$.

(N/A) Steps of construction:
$(1)$ Draw any ray $BX$ and from that obtain the line segment $BC$ of length $6\,cm$.
$(2)$ Construct ray $BY$ such that $\angle YBC = 90^{\circ}$.
$(3)$ Taking $B$ as the centre and radius $9\,cm$,draw an arc to intersect $BY$ at $M$.
$(4)$ Draw line segment $CM$. Draw the perpendicular bisector of $CM$ to intersect $BM$ at $A$.
$(5)$ Draw line segment $AC$.
Then,$\Delta ABC$ is the required triangle in which $\angle B$ is a right angle,$BC = 6\,cm$ and $AB + AC = 9\,cm$.